document.write( "Question 609833: I have also been asked to solve this geometric sequence problem and show the work however I am at a standstill with it. Could you help me with figuring this out, so that I can understand how to do this type of work?
\n" ); document.write( " A person deposited $500 in a savings account that pays 5% annual interest that is compounded yearly. At the end of 10 years, how much money will be in the savings account?
\n" ); document.write( "

Algebra.Com's Answer #383961 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
You can do this the long way without a formula
\n" ); document.write( "After 1 year:
\n" ); document.write( "\"+500+%2B+.05%2A500+\" in savings account
\n" ); document.write( "-----------
\n" ); document.write( "After 2 years:
\n" ); document.write( "\"+500+%2B+.05%2A500+%2B+.05%2A%28+500+%2B+.05%2A500+%29+\"
\n" ); document.write( "Here's the trick: factor out \"+500+%2B+.05%2A500+\"
\n" ); document.write( "\"+%28+500+%2B+.05%2A500+%29%2A%28+1+%2B+.05+%29%0D%0ANow+factor+out+%7B%7B%7B+500+\" from the 1st term:
\n" ); document.write( "\"+500%2A%28+1+%2B+.05+%29%2A%28+1+%2B+.05+%29+\"
\n" ); document.write( "\"+500%2A%28+1+%2B+.05+%29%5E2+\"
\n" ); document.write( "----------
\n" ); document.write( "After 3 years:
\n" ); document.write( "\"+500%2A%28+1+%2B+.05+%29%5E2+%2B+.05%2A%28+500%2A%28+1+%2B+.05+%29%5E2%29+\"
\n" ); document.write( "Now factor out \"+500%2A%28+1+%2B+.05+%29%5E2+\"
\n" ); document.write( "\"+500%2A%28+1+%2B+.05+%29%5E2+%2A%28+1+%2B+.05+%29+\"
\n" ); document.write( "\"+500%2A%28+1+%2B+.05+%29%5E3+\"
\n" ); document.write( "----------
\n" ); document.write( "As you can see, the formula is \"+500%2A%28+1+%2B+.05+%29%5En+\"
\n" ); document.write( "where \"+n+\" is the number of years
\n" ); document.write( "After \"+10+\" years,
\n" ); document.write( "\"+A+=+500%2A+1.05%5E10+\"
\n" ); document.write( "\"+log%28+A+%29+=+log%28+500+%29+%2B+10%2Alog%28+1.05+%29+\"
\n" ); document.write( "\"+log%28+A+%29+=+2.6989+%2B+10%2A.02119+\"
\n" ); document.write( "\"+log+%28+A+%29+=+2.9108+\"
\n" ); document.write( "\"+A+=+10%5E2.9108+\"
\n" ); document.write( "\"+A+=+814.33+\"
\n" ); document.write( "After 10 years, there is $814.33 in the account
\n" ); document.write( "check:
\n" ); document.write( "\"+814.33+=+500%2A1.05%5E10+\"
\n" ); document.write( "\"+814.33%2F500+=+1.05%5E10+\"
\n" ); document.write( "\"+1.629+=+1.629+\"
\n" ); document.write( "OK\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );