document.write( "Question 56496This question is from textbook Algerbra for College Students
\n" ); document.write( ": The perimeter of a rectangle is 114 centimeters. If the ratio of its width to its length is 7 to 12, find the dimenŽsions of the rectangle. \n" ); document.write( "
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The perimeter of a rectangle is 114 centimeters. If the ratio of its width to it's length is 7 to 12, find the dimensions of the rectangle.
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\n" ); document.write( " That means that 7L = 12W
\n" ); document.write( "Using that equation:
\n" ); document.write( "7L = 12W
\n" ); document.write( "L = (12/7)W
\n" ); document.write( ":
\n" ); document.write( "We know 2L + 2W = 114
\n" ); document.write( ":
\n" ); document.write( "Substitute (12/7)W for L:
\n" ); document.write( ":
\n" ); document.write( "2(12/7)W + 2W = 114
\n" ); document.write( ":
\n" ); document.write( "(24/7)W + 2W = 114
\n" ); document.write( ":
\n" ); document.write( "Mult equation by 7 to get rid of that annoying denominator:
\n" ); document.write( "24W + 14W = 798
\n" ); document.write( "38W = 798
\n" ); document.write( "W = 798/38
\n" ); document.write( "W = 21 cm is the width
\n" ); document.write( ":
\n" ); document.write( "Remember L = (12/7)W
\n" ); document.write( "L = 12/7 * 21
\n" ); document.write( "L = 12 * 3
\n" ); document.write( "L = 36 cm is the length
\n" ); document.write( ":
\n" ); document.write( "Check by reducing the fraction: 21/36 = 7/12 \n" ); document.write( "
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