document.write( "Question 609447: A does 3/10 of a work in 6 days .He then calls in B and they finish the work in 7 days more .How long would B take to do the work by himself?\r
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\n" ); document.write( "\n" ); document.write( "A,B,C working together ,can do a piece of work in 18 days .A can do it alone in 72 days .After working for 6 days ,A fell ill.How long will B and C together take to finish the remaining work?
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Algebra.Com's Answer #383792 by ankor@dixie-net.com(22740)\"\" \"About 
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A does 3/10 of a work in 6 days .He then calls in B and they finish the work in 7 days more .
\n" ); document.write( "How long would B take to do the work by himself?
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\n" ); document.write( "Find how long (a), it takes for A to do the job by himself
\n" ); document.write( "\"3%2F10\"a = 6
\n" ); document.write( "3a = 6(10)
\n" ); document.write( "3a = 60
\n" ); document.write( "a = 60/3
\n" ); document.write( "a = 20 days, A by himself
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\n" ); document.write( "Let b = B's time by himself
\n" ); document.write( "Let the completed job = 1
\n" ); document.write( "A works a total of 13 days so we have:
\n" ); document.write( "\"13%2F20\" + \"7%2Fb\" = 1
\n" ); document.write( "multiply by 20b
\n" ); document.write( "13b + 20(7) = 20b
\n" ); document.write( "140 = 20b - 13b
\n" ); document.write( "140 = 7b
\n" ); document.write( "b = 140/7
\n" ); document.write( "b = 20 days, B by himself
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\n" ); document.write( "A,B,C working together ,can do a piece of work in 18 days. A can do it alone in 72 days.
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\n" ); document.write( "Find how long (bc) for B&C to do the job (we can treat B&C as a single person)
\n" ); document.write( "\"18%2F72\" + \"18%2F%28bc%29\" = 1
\n" ); document.write( "Multiply by 72bc
\n" ); document.write( "18bc + 18(72) = 72bc
\n" ); document.write( "1296 = 72bc - 18bc
\n" ); document.write( "1296 = 54bc
\n" ); document.write( "bc = 1296/54
\n" ); document.write( "bc = 24 days B*C only working
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\n" ); document.write( "After working for 6 days, A fell ill.
\n" ); document.write( " How long will B and C together take to finish the remaining work?
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\n" ); document.write( "Let t = time worked by B*C to finish the job
\n" ); document.write( "\"6%2F72\" + \"%28t%2B6%29%2F24\" = 1
\n" ); document.write( "multiply by 72, results
\n" ); document.write( "6 + 3(t+6) = 72
\n" ); document.write( "6 + 3t + 18 = 72
\n" ); document.write( "3t = 72 -24
\n" ); document.write( "3t = 48
\n" ); document.write( "t = 48/3
\n" ); document.write( "t = 16 days for B&C to finish the job, when A leaves after 6 days
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