document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=609372>Question 609372</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A Goat can eat all the grass in a farmer's field, in 12 days, whereas a cow can finish it in 15 days and a horse in 20 days. How long will it be before all the grass is eaten if all three animals graze in the field. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #383689 by </B><A HREF=/tutors/aboutme.mpl?userid=flame8855><B>flame8855(424)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=flame8855><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=flame8855><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=383689\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 12 goat = 1 field per day (fpd)<BR>\n" );
document.write( "15 cow = 1 fpd<BR>\n" );
document.write( "20 horse = 1 fpd\r<BR>\n" );
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document.write( "1 goat eats at the rate of 1/12 fpd<BR>\n" );
document.write( "1 cow eats at the rate of 1/15 fpd<BR>\n" );
document.write( "1 horse eats at rate of 1/20 fpd\r<BR>\n" );
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document.write( "rate of consumption = 1/12 + 1/15 + 1/20 fpd \r<BR>\n" );
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document.write( "thats 5/60 + 4/60 + 3/60 = 12/60 fpd\r<BR>\n" );
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document.write( "= 1/5 of a field a day.\r<BR>\n" );
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document.write( "I make it 5 days </SPAN>\n" );
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