document.write( "Question 609327: what is the value of nCr when r=n \n" ); document.write( "
Algebra.Com's Answer #383684 by math-vortex(648)\"\" \"About 
You can put this solution on YOUR website!
Hi, there--
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\n" ); document.write( "There are (at least) to ways you can think about this. First, we have a formula for nCr.\r
\n" ); document.write( "\n" ); document.write( "nCr = n! / (r!(n-r)!)
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\n" ); document.write( "Since n=r, we can substitute n for r in the formula.
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\n" ); document.write( "nCn = n! / (n!(n-n)!)
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\n" ); document.write( "Simplify.
\n" ); document.write( "nCn = n! / (n! 0!)
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\n" ); document.write( "n! over n! is 1. By definition 0! is also 1. So nCn = 1 when n=r.
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\n" ); document.write( "Another way to think about this is to remember what combinations mean. How many ways can I choose r objects from a group of n objects. (Order does not matter.) When n=r, I'm choosing all the objects. Order does not matter, so there is only one way to choose.
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\n" ); document.write( "I hope this helps. Feel free to email if you still have questions about this.
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\n" ); document.write( "Ms.Figgy
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