document.write( "Question 609319: how many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 10% antifreeze to get a mixture that is 70% antifreeze \n" ); document.write( "
Algebra.Com's Answer #383669 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! how many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 10% antifreeze to get a mixture that is 70% antifreeze \n" ); document.write( "----------------- \n" ); document.write( "alcohol + alcohol = alcohol \n" ); document.write( "0.80x + 0.10*100 = 0.70(x+100) \n" ); document.write( "--- \n" ); document.write( "80x + 10*100 = 70x + 70*100 \n" ); document.write( "10x = 60*100 \n" ); document.write( "x = 600 gallons (amt. of 80% solution needed) \n" ); document.write( "---- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================= \n" ); document.write( " |