document.write( "Question 609319: how many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 10% antifreeze to get a mixture that is 70% antifreeze \n" ); document.write( "
Algebra.Com's Answer #383669 by stanbon(75887)\"\" \"About 
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how many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 10% antifreeze to get a mixture that is 70% antifreeze
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\n" ); document.write( "alcohol + alcohol = alcohol
\n" ); document.write( "0.80x + 0.10*100 = 0.70(x+100)
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\n" ); document.write( "80x + 10*100 = 70x + 70*100
\n" ); document.write( "10x = 60*100
\n" ); document.write( "x = 600 gallons (amt. of 80% solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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