document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=609316>Question 609316</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the smaller of two numbers is 3 less than the greater.  if the greater is decreased by twice the smaller, the result is -5.  find the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #383666 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=383666\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the smaller of two numbers is 3 less than the greater. if the greater is decreased by twice the smaller, the result is -5. find the two numbers.<BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "s = g - 3<BR>\n" );
document.write( "g - 2s = -5<BR>\n" );
document.write( "------<BR>\n" );
document.write( "Substitute for \"s\" and solve for \"g\":<BR>\n" );
document.write( "g - 2(g-3) = -5<BR>\n" );
document.write( "g -2g+6 = -5<BR>\n" );
document.write( "-g = -11<BR>\n" );
document.write( "greater number  = 11 <BR>\n" );
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document.write( "Solve for \"s\":<BR>\n" );
document.write( "s = g -3<BR>\n" );
document.write( "smaller number = 11-3 = 8<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "====================== </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );