document.write( "Question 609079: log(14x+45)-log 7=log 2-log x \n" ); document.write( "
Algebra.Com's Answer #383524 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! log(14x+45)-log 7=log 2-log x \n" ); document.write( "log((14x+45)/7) = log 2-log x \n" ); document.write( "log((14x+45)/7) = log(2/x) \n" ); document.write( "(14x+45)/7 = 2/x \n" ); document.write( "cross-multiply: \n" ); document.write( "x(14x+45) = 7*2 \n" ); document.write( "14x^2+45x = 49 \n" ); document.write( "14x^2+45x-49 = 0 \n" ); document.write( "solving for x by using the quadratic formula yields: \n" ); document.write( "x = {0.86, -4.1} \n" ); document.write( "we can throw out the negative solution (extraneous) leaving: \n" ); document.write( "x = 0.86 \n" ); document.write( ". \n" ); document.write( "Details of quadratic formula: \n" ); document.write( "
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