document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=609005>Question 609005</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many square feet of aluminum materials will be needed in order to construct an open top right cylindrical tank which is 6 feet high and has a diameter of 2 feet,if only 5% of the total surface of the cylinder is to be allowed for waste?.please help.please give solution or steps. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #383500 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=383500\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how many square feet of aluminum materials will be needed in order to construct an open top right cylindrical tank which is 6 feet high and has a diameter of 2 feet, if only 5% of the total surface of the cylinder is to be allowed for waste?<BR>\n" );
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document.write( "The equation for the surface area of an open top cylinder<BR>\n" );
document.write( "S.A. = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2pi%2Ar%2Ah ALIGN=MIDDLE  ALT=\"2pi%2Ar%2Ah\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2Ar%5E2 ALIGN=MIDDLE  ALT=\"pi%2Ar%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "However the round bottom will be cut out of a 2 by 2 ft square, which would have some waste. <BR>\n" );
document.write( "The side would be a rectangle so no waste there.<BR>\n" );
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document.write( "This cylinder will have a radius of half the diameter (1 ft) and a height of 6 ft<BR>\n" );
document.write( "S.a. = side + square for the bottom<BR>\n" );
document.write( "S.A. = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2pi%2A1%2A6 ALIGN=MIDDLE  ALT=\"2pi%2A1%2A6\"   DISABLED_style= \"max-width:90%; height:auto;\" > + 2^2<BR>\n" );
document.write( "S.A. = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12pi+%2B+4 ALIGN=MIDDLE  ALT=\"12pi+%2B+4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "S.A. = 37.7 + 4<BR>\n" );
document.write( "S.A. = 41.7 sq/ft required<BR>\n" );
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document.write( "Waste from the round bottom: 4 - <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2A1%5E2 ALIGN=MIDDLE  ALT=\"pi%2A1%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > = .86 sq/ft wasted<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=.86%2F41.7 ALIGN=MIDDLE  ALT=\".86%2F41.7\"   DISABLED_style= \"max-width:90%; height:auto;\" > *100 ~ 2% wasted  </SPAN>\n" );
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