document.write( "Question 608917: ln(lne(exponent -x) =ln3\r
\n" ); document.write( "\n" ); document.write( "ln6x-ln(x+1)=ln4\r
\n" ); document.write( "\n" ); document.write( "lnx+3ln2=ln2/x \n" ); document.write( "
Algebra.Com's Answer #383425 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
ln(lne(exponent -x) =ln3
\n" ); document.write( "lne^-x=-x (log of base raised to a power=power)
\n" ); document.write( "ln(-x)=ln(3)
\n" ); document.write( "-x=3
\n" ); document.write( "x=3
\n" ); document.write( "..
\n" ); document.write( "ln6x-ln(x+1)=ln4
\n" ); document.write( "ln6x-ln(x+1)-ln4=0
\n" ); document.write( "ln6x-(ln(x+1)+ln4)=0
\n" ); document.write( "place under single log
\n" ); document.write( "ln[6x/((x+1)*4)]=0
\n" ); document.write( "convert to exponential form:
\n" ); document.write( "e^0=6x/((x+1)*4)=1
\n" ); document.write( "6x=4x+4
\n" ); document.write( "2x=4
\n" ); document.write( "x=2
\n" ); document.write( "..
\n" ); document.write( "lnx+3ln2=ln2/x
\n" ); document.write( "I will assume last term is meant to be ln(2/x) instead of (ln2)/x which I am not able to solve.
\n" ); document.write( "lnx+3ln2=ln(2/x)
\n" ); document.write( "lnx+3ln2=ln2-lnx
\n" ); document.write( "2lnx+2ln2=0
\n" ); document.write( "place under single log
\n" ); document.write( "ln[x^2*2^2]=0
\n" ); document.write( "ln[4x^2]=0
\n" ); document.write( "convert to exponential form
\n" ); document.write( "e^0=4x^2=1
\n" ); document.write( "x^2=1/4
\n" ); document.write( "x=-1/2 (reject, x>0)
\n" ); document.write( "or
\n" ); document.write( "x=1/2 \n" ); document.write( "
\n" );