document.write( "Question 608819: You have 2 mixtures of a saline solution that are 12% by volume, and 20% by volume. You need 6 gallons of a solution that is 18% by volume for an experiment. How much of the 12% and the 20% solutions should you mix together? \n" ); document.write( "
Algebra.Com's Answer #383391 by mananth(16946)\"\" \"About 
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Solution I --12%---x gal
\n" ); document.write( "Solution II--20%---(6-x)gal\r
\n" ); document.write( "\n" ); document.write( "Mixture total ---- 18% -----6 gal\r
\n" ); document.write( "\n" ); document.write( "12%*x+(6-x)*20%= 6*18%\r
\n" ); document.write( "\n" ); document.write( "multiply equation by 100\r
\n" ); document.write( "\n" ); document.write( "12x+(6-x)*20 = 108\r
\n" ); document.write( "\n" ); document.write( "12x+120-20x=108\r
\n" ); document.write( "\n" ); document.write( "12x-20x=108-120
\n" ); document.write( "-8x=-12x
\n" ); document.write( "/-8
\n" ); document.write( "x=-12/8
\n" ); document.write( "x=3/4 gallons --- 6% solution\r
\n" ); document.write( "\n" ); document.write( "Balance of 6 gallons is 20% solution
\n" ); document.write( "6-3/4
\n" ); document.write( "= 5 1/4 gallons\r
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