document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=608794>Question 608794</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the standard score (z) such that the area below the mean and below z is about 16% of the area under the normal curve. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #383380 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=383380\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the standard score (z) such that the area below the mean and below z is about 16% of the area under the normal curve.<BR>\n" );
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document.write( "Using a TI-8r I get:<BR>\n" );
document.write( "z = invNorm(0.16) = -0.9945<BR>\n" );
document.write( "====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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