document.write( "Question 608704: In the process of completing the square, 3x²+7x=12 becomes x^2+7/4x=4\r
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Algebra.Com's Answer #383356 by Edwin McCravy(20060) $\"\"$ $\"About$

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3x² + 7x = 12
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document.write( "So you asked if that becomes:  x² + x = 4?\r\n" );
document.write( "No because the first step is to divide through by the\r\n" );
document.write( "coefficient of x², which is 3. And we divide all the terms,\r\n" );
document.write( "on both sides by 3 \r\n" );
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document.write( "x² + x = \r\n" );
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document.write( "           x² + x = 4 \r\n" );
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document.write( " So  has the wrong enominator.\r\n" );
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document.write( "But it seems a shame to stop here and not go on and\r\n" );
document.write( "complete the square.  Let's do it just for fun:\r\n" );
document.write( "(You can print it for future use, because you're\r\n" );
document.write( "going to have to learn how to do that soon.\r\n" );
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document.write( "multiply  times , get \r\n" );
document.write( "Square . get \r\n" );
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document.write( "Add that to BOTH sides of the equation, to keep\r\n" );
document.write( "it balanced.\r\n" );
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document.write( "So now we have:\r\n" );
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document.write( "x² + x+ = 4+\r\n" );
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document.write( "That factors as:\r\n" );
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document.write( "(x + )² = \r\n" );
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document.write( "Now we use the principle of square roots:\r\n" );
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document.write( " x +  = \r\n" );
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document.write( " x +  = \r\n" );
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document.write( "             x = \r\n" );
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document.write( "             x = \r\n" );
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document.write( "Edwin

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