document.write( "Question 608511: what is the equation of a line that is perpendicular to the line y=-2/5x-5 and passes through the point 6,1 \n" ); document.write( "
Algebra.Com's Answer #383285 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "Using the standard slope-intercept form for an equation of a line y = mx + b
\n" ); document.write( " where m is the slope and b the y-intercept

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\n" ); document.write( "equation of a line that is perpendicular to the line y=-2/5x-5 and passes through the point 6,1
\n" ); document.write( "New Line: slope = 5/2 (Negative reciprocal of -2/5)
\n" ); document.write( " y = (5/2)x + b
\n" ); document.write( " 1 = (5/2)6 + b
\n" ); document.write( " -14 = b
\n" ); document.write( " y = (5/2)x -14 \n" ); document.write( "
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