document.write( "Question 48127: We were told to solve these systems by graphing but, on the graph he has a place for six points it is mapped out as:\r
\n" ); document.write( "\n" ); document.write( "x y1 y2
\n" ); document.write( "0 0 0
\n" ); document.write( "0 0 0\r
\n" ); document.write( "\n" ); document.write( "My first problem is x + 2y = 4
\n" ); document.write( " x + 2y = -2\r
\n" ); document.write( "\n" ); document.write( "My solutions were x = (0,2) (4,0)
\n" ); document.write( " y = (-4,1)(0.-4)
\n" ); document.write( "How do i graph this where do I place the numbers on the graph. \n" ); document.write( "

Algebra.Com's Answer #38323 by rchill(405) $\"\"$ $\"About$

You can put this solution on YOUR website!
Before doing any substitutions, always solve for y. Doing so yields $\"y=-expr%281%2F2%29x%2B2\"$ and $\"y=-expr%281%2F2%29x-1\"$ . Because the slopes are exactly the same, that means the lines are parallel. If you substitute 0 for x in both equations you get y=2 for the first equation and y=-1 for the second equation. The graph is:
\n" ); document.write( " $\"graph%28200%2C200%2C-5%2C5%2C-5%2C5%2C-x%2F2%2B2%2C-x%2F2-1%29\"$ \n" ); document.write( "

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