document.write( "Question 608446: Malik popped a ball staight up with an initial upward velocity of 45 feet per second. the height h, in feet, of the ball above the ground is modeled by the equation h = 2 + 45t - 16t^2. How long was the ball in the air if the catcher catches the ball when it is 2 feet above the ground? \n" ); document.write( "
Algebra.Com's Answer #383196 by nerdybill(7384) You can put this solution on YOUR website! Given: \n" ); document.write( "h = 2 + 45t - 16t^2 \n" ); document.write( "set h to 2 and solve for t: \n" ); document.write( "2 = 2 + 45t - 16t^2 \n" ); document.write( "0 = 45t - 16t^2 \n" ); document.write( "0 = t(45 - 16t) \n" ); document.write( ". \n" ); document.write( "t = {0,45/16} \n" ); document.write( "t = {0,2.81} \n" ); document.write( "answer: 2.8 seconds \n" ); document.write( " \n" ); document.write( " |