document.write( "Question 608152: an arrow is fired into the air with an initial velocity of 160 feet per second. The height in feet of the arrow t seconds after it was shot into the air is given by the function h(t)= -16t^2+160t. find the maximum height of the arrow. \n" ); document.write( "
Algebra.Com's Answer #383073 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Well, not exactly.\r
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\n" ); document.write( "\n" ); document.write( "Your height function ignores the initial height of the tip of the arrow at the time of release. This value is other than zero unless the archer is standing in a hole of sufficient depth such that the tip of the arrow is exactly at ground level at the time it is released.\r
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\n" ); document.write( "\n" ); document.write( "Where is the initial height. We'll just accept the \"archer in a hole\" scenario for the time being and assume that .\r
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\n" ); document.write( "\n" ); document.write( "The graph of your function is a parabola. Because of the negative lead coefficient, the parabola opens downward, meaning that the vertex is a maximum value of the function. The coordinate of the vertex of a parabola described by the function such as this one is given by:\r
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\n" ); document.write( "\n" ); document.write( "Calculate \r
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\n" ); document.write( "\n" ); document.write( "Once you have a value for the coordinate of the vertex, calculate\r
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\n" ); document.write( "\n" ); document.write( "to get the value of the function at the vertex, i.e. the maximum value of the height function. If you decide later that is actually something other than zero, you can just add it on at the end.\r
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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