document.write( "Question 608072: f(x)=2-2x^2\r
\n" ); document.write( "\n" ); document.write( "Estimate the intervals on which the function is increasing or decreasing and estimate any relative maxima or minima. Thanks and could you also show work.
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Algebra.Com's Answer #383034 by nerdybill(7384)\"\" \"About 
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f(x)=2-2x^2
\n" ); document.write( "Estimate the intervals on which the function is increasing or decreasing and estimate any relative maxima or minima. Thanks and could you also show work
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\n" ); document.write( "This is a \"quadratic\" because it is a polynomial of degree 2.
\n" ); document.write( "Because it's a quadratic, it is a parabola.
\n" ); document.write( "We know the parabola opens downward because the coefficient associated with the x^2 term is negative (think sad face).
\n" ); document.write( "Since it is a parabola that opens downwards, we know the vertex is at the MAXIMUM.
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\n" ); document.write( "Axis of symmetry:
\n" ); document.write( "x = -b/(2a)
\n" ); document.write( "x = -0/(2(-2))
\n" ); document.write( "x = -0/(-4)
\n" ); document.write( "x = 0
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\n" ); document.write( "Increasing interval:
\n" ); document.write( "(-oo, 0)
\n" ); document.write( "Decreasing interval:
\n" ); document.write( "(0, +oo)
\n" ); document.write( "where oo is for infinity
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\n" ); document.write( "Maximum:
\n" ); document.write( "f(0)=2-2(0)^2
\n" ); document.write( "f(0)=2
\n" ); document.write( "so, max is at (0,2)
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