document.write( "Question 608023: Hi, I hope someone helps me with this trigonometric equations problem.\r
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document.write( "How do you get the solution set of cos^2 2x + 3sin2x = 3 ?\r
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document.write( "Also please include the steps. I don't understand our lesson well, especially the part where the reference angle enters. I don't get it at all. Thank yoy for your help! \n" );
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Algebra.Com's Answer #383020 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! cos^2 2x + 3sin2x = 3 \n" ); document.write( "----------------- \n" ); document.write( "cos^2 = 1 - sin^2 \n" ); document.write( "1 - sin^2 + 3sin = 2 \n" ); document.write( "sin^2 - 3sin + 1 = 0 \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-------- \n" ); document.write( "sin(2x) =~ 0.381966 (Ignore the sin > 1 unless you want complex angles) \n" ); document.write( "2x =~ 0.39192 + 2n*pi radians, n = 0,1,2,3... \n" ); document.write( "x = 0.19596 radians + n*pi, n = 0,1,2,3... \n" ); document.write( "x = pi - 0.19596 + n*pi, n = 0,1,2,3... \n" ); document.write( " \n" ); document.write( " |