document.write( "Question 56456: A freight train left a station and traveled at 30 mph. Two hours later, an express train left the same station and traveled in the same direction at 50 mph (on a different track). In how many hours did the express overtake the freight train? \n" ); document.write( "
Algebra.Com's Answer #38300 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A freight train left a station and traveled at 30 mph. Two hours later, an express train left the same station and traveled in the same direction at 50 mph (on a different track). In how many hours did the express overtake the freight train? \n" ); document.write( ": \n" ); document.write( "Let t = time it took the express to overtake the freight \n" ); document.write( ": \n" ); document.write( "Then (t+2) time the freight was traveling when it was overtaken \n" ); document.write( ": \n" ); document.write( "We know that when the express overtakes the freight, they will have traveled the same distance. Another words; Express dist = Freight dist \n" ); document.write( ": \n" ); document.write( "distance = speed * time: \n" ); document.write( ": \n" ); document.write( "A simple distance equation \n" ); document.write( " Express dist = freight dist; (as we said before). \n" ); document.write( " 50t = 30(t+2) \n" ); document.write( " 50t = 30t + 60 \n" ); document.write( "50t - 30t = 60 \n" ); document.write( "20t = 60 \n" ); document.write( "t = 60/20 \n" ); document.write( "t = 3 hrs for the express to overtake the freight \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check our solution using distance: \n" ); document.write( "50 * 3 = 30 * (3 + 2) \n" ); document.write( "150 = 150 \n" ); document.write( ": \n" ); document.write( "Make sense to you?\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |