document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=607845>Question 607845</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This may seem easy, but I don't get how to find the answer to this\r<BR>\n" );
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document.write( "1. F <-> G\r<BR>\n" );
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document.write( "with the final answer of -F <-> -G </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #382923 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=382923\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If F <--> G, then (F -> G) * (G -> F)\r<BR>\n" );
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document.write( "We can then use simplification to get F -> G and G -> F\r<BR>\n" );
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document.write( "We can then use transposition to get ~G -> ~F and ~F -> ~G\r<BR>\n" );
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document.write( "From there, we can then recombine the two last expressions using the conjunction rule to get (~G -> ~F) * (~F -> ~G)\r<BR>\n" );
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document.write( "Finally, you can then use the material equivalence rule to go from (~G -> ~F) * (~F -> ~G) to ~G <--> ~F\r<BR>\n" );
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document.write( "Hopefully these steps and ideas make sense. If not, let me know. Thanks. </SPAN>\n" );
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