document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=607707>Question 607707</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Train A and B are traveling in the same direction,on parallel tracks. Train A is traveling at 100 miles per hour ans train B is traveling at 120 miles per hour.Train A passes a station at 8:10 P.M. If train B passes the same station at 8:22 P.M., at what time will train B catch up to train A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #382911 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=382911\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Train A and B are traveling in the same direction,on parallel tracks. Train A is traveling at 100 miles per hour ans train B is traveling at 120 miles per hour.Train A passes a station at 8:10 P.M. If train B passes the same station at 8:22 P.M., at what time will train B catch up to train A?<BR>\n" );
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document.write( "In the 12 minutes from 810 to 822, Train A is (12/60)*100 miles ahead<BR>\n" );
document.write( "= 20 miles.<BR>\n" );
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document.write( "Train B passes the station at 822, Train A is 20 miles ahead.<BR>\n" );
document.write( "Train B gains on Train A at 20 mile/hr (100 - 80)<BR>\n" );
document.write( "20/20 = 1 hour<BR>\n" );
document.write( "822 + 1 = 9:22<BR>\n" );
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