document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=607700>Question 607700</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A hose can fill a pool in 6 hours. A second hose can fill the same pool in 4 hours. How long will it take to fill the pool if both hoses are used at the same time? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #382868 by </B><A HREF=/tutors/aboutme.mpl?userid=chippewapride><B>chippewapride(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chippewapride><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=382868\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1st hose can fill a pool in 6 hours. Equation= 1/6  because it can finish 1/6 of the work in 1 hour.<BR>\n" );
document.write( "2nd hose can fill a pool in 4 hours. Equation=1/4 because it can finish 1/4 of the work in 1 hour.<BR>\n" );
document.write( "When the work together: equation: 1/6 + 1/4 = 1/t <BR>\n" );
document.write( "They can finish 1/t of the time when they work together.<BR>\n" );
document.write( "Now solve for t.<BR>\n" );
document.write( "Find Lowest Common Denominator (LCD) : 24t<BR>\n" );
document.write( "1/6 times 24t= 4t<BR>\n" );
document.write( "1/4 times 24t= 6t<BR>\n" );
document.write( "1/t times 24t= 24<BR>\n" );
document.write( "Now solve.<BR>\n" );
document.write( "4t+6t=24<BR>\n" );
document.write( "10t=24<BR>\n" );
document.write( "t=24/10<BR>\n" );
document.write( "t=144/60 (60 because total minutes per hour<BR>\n" );
document.write( "t=  2 hours (120 minutes) and 24 minutes </SPAN>\n" );
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