document.write( "Question 607720: what is the area of the triangle when its length is 6yd and its width is two feet? \n" ); document.write( "
Algebra.Com's Answer #382867 by jim_thompson5910(35256) ![]() You can put this solution on YOUR website! This sounds like a rectangle (and NOT a triangle)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Area = length * width\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A = LW\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A = 18*2 ... Note: 6 yds = 6*3 = 18 ft\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A = 36\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the area of the rectangle is 36 square feet\r \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------------------------------------------------------------- \n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Jim \n" ); document.write( "-------------------------------------------------------------------------------------------------------------- \n" ); document.write( " |