document.write( "Question 607617: How do you solve 5x squared plus 16x minus 84 equals 0 using the quadratic equation\r
\n" ); document.write( "\n" ); document.write( "How do you solve 4x squared minus 12x plus 9 equals 0 using the quadratic equation
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Algebra.Com's Answer #382854 by KMST(5328)\"\" \"About 
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There are other ways to solve a quadratic equation, but using the quadratic formula always works if you are careful in doing your calculations.
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\n" ); document.write( "SOLVING QUADRATIC EQUATIONS USING THE QUADRATIC FORMULA:
\n" ); document.write( "A quadratic equation is an equation of the form
\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\" where the coefficients b, and c are any number and a is not zero.
\n" ); document.write( "Its solutions are given by the quadratic formula:
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "To solve a quadratic equation by using the quadratic formula, you need to determine the values for a, b, and c in the equation you are solving. You then plug those values into the formula, and calculate very carefully.
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\n" ); document.write( "FOR \"5x%5E2%2B16x-84=0\", a=5, b=16, and c=-84,
\n" ); document.write( "so
\n" ); document.write( "The answers are
\n" ); document.write( "\"x=%28-16%2B44%29%2F10=28%2F10=highlight%2814%2F5%29\" and \"x=%28-16-44%29%2F10=-60%2F10=highlight%28-6%29\"
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\n" ); document.write( "FOR \"4x%5E2-12x%2B9=0\", a=4, b=-12, and c=9,
\n" ); document.write( "so
\n" ); document.write( "The one and only answer is
\n" ); document.write( "\"highlight%28x=3%2F2%29\"
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\n" ); document.write( "THE OTHER WAYS TO SOLVE THOSE EQUATIONS:
\n" ); document.write( "Factoring, with some work, we get \"5x%5E2%2B16x-84=%285x-14%29%28x%2B6%29\" ,
\n" ); document.write( "so the equation \"5x%5E2%2B16x-84=0\" turns into
\n" ); document.write( "\"%285x-14%29%28x%2B6%29=0\" with solutions when \"5x-14=0\" --> \"x=14%2F5\"
\n" ); document.write( "and when \"x%2B6=0\" --> \"x=-6\"
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\n" ); document.write( "The factoring is much easier for \"4x%5E2-12x%2B9=0\", because it is obvious that \"4x%5E2-12x%2B9=%282x-3%29%5E2\" . It's the square of a binomial, one of the special products you are taught about in polynomials.
\n" ); document.write( "The only solution for \"%282x-3%29%5E2=0\" is the value for x that makes
\n" ); document.write( "\"2x-3=0\" --> \"2x-3=0\" --> \"2x=3\" --> \"x=3%2F2\".
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\n" ); document.write( "FACTORING \"5x%5E2%2B16x-84\" :
\n" ); document.write( "If it can be factored, it will be
\n" ); document.write( "\"5x%5E2%2B16x-84=%285x%2Bd%29%28x%2Bf%29=5x%5E2%2B%28d%2B5f%29x%2Bdf%29\" so we know that:
\n" ); document.write( "\"df=-84\" so d and f have different signs, and
\n" ); document.write( "two factors (one positive and one negative) whose product is \"5%2Adf=-420=5%2A%28-84%29=%28d%29%2A%285f%29\" will be such that \"d%2B5f=16\"
\n" ); document.write( "There are many pairs of factors to 420 (we can worry about the signs later):
\n" ); document.write( "420=(1)(420)=(2)(210)=(3)(140)=(4)(105)=(5)(84)=(6)(70)=(7)(60)=(10)(42)=(12)(35)=(14)(30)=(15)(28)=(20)(21),
\n" ); document.write( "but the only pair that adds up to 16 (we consider sign now) is 30 and -14 (30-14=16).
\n" ); document.write( "So, before collecting like term, the product could have been
\n" ); document.write( "\"5x%5E2%2B30x-14x-84\" and that is easier to factor by grouping, as follows:
\n" ); document.write( "\"5x%5E2%2B30x-14x-84=5x%28x%2B6%29-14%28x%2B6%29=%285x-14%29%28x%2B6%29\"
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