document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=607683>Question 607683</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 94 feet, and the area of the rectangle is 90ft^2. Find the dimensions of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #382832 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=382832\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter\r<BR>\n" );
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document.write( "P = 2L+2W\r<BR>\n" );
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document.write( "94 = 2L+2W\r<BR>\n" );
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document.write( "94 - 2L = 2W\r<BR>\n" );
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document.write( "2W = -2L + 94\r<BR>\n" );
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document.write( "W = -2L/2 + 94/2\r<BR>\n" );
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document.write( "W = -L + 47\r<BR>\n" );
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document.write( "Area\r<BR>\n" );
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document.write( "A = LW\r<BR>\n" );
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document.write( "A = L(-L + 47)\r<BR>\n" );
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document.write( "A = -L^2 + 47L\r<BR>\n" );
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document.write( "90 = -L^2 + 47L\r<BR>\n" );
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document.write( "0 = -L^2 + 47L - 90\r<BR>\n" );
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document.write( "-L^2 + 47L - 90 = 0\r<BR>\n" );
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document.write( "L^2 - 47L + 90 = 0\r<BR>\n" );
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document.write( "From here, solve the equation for L (using the quadratic formula). Make sure to toss out any negative answers.\r<BR>\n" );
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document.write( "Once you get a solution for L, use it to find W.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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