document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=607629>Question 607629</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation for x (Show work) Exact answers (no decimals)<BR>\n" );
document.write( "10^logx = 33 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #382806 by </B><A HREF=/tutors/aboutme.mpl?userid=Yemi><B>Yemi(10)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Yemi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=382806\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Take the logarithm to base ten of both side.(Note that log 10 to base ten is one.).Then you have log x=log 33.If the log of two numbers are equal,then the numbers are equal.Therefore, x=33. </SPAN>\n" );
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