document.write( "Question 56437: I think I get scared of fractions and algebra. I am not sure I ask previously in the correct way. Can you help with this? Thanks!\r
\n" ); document.write( "\n" ); document.write( "solve for x:\r
\n" ); document.write( "\n" ); document.write( " 13 4
\n" ); document.write( "_______ = _______\r
\n" ); document.write( "\n" ); document.write( " x-1 x+2\r
\n" ); document.write( "\n" ); document.write( "or 13 over x-1 equal(=) to 4 over x +2. Maybe that is clear enough. \r
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\n" ); document.write( "\n" ); document.write( "any assitance would be appreciated.''.
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Algebra.Com's Answer #38279 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
13/(X-1)=4/(X+2)
\n" ); document.write( "CROSS MULTIPLYING WE GET
\n" ); document.write( "4(X-1)=13(X+2)
\n" ); document.write( "4X-4=13X+26
\n" ); document.write( "4X-13X=26+4
\n" ); document.write( "-9X=30
\n" ); document.write( "X=30/-9
\n" ); document.write( "X=-10/3
\n" ); document.write( "PROOF
\n" ); document.write( "13[(-10/3)-1]=4/[(-10/3)+2]
\n" ); document.write( "13[(-10/3)+2]=4[(-10/3)-1]
\n" ); document.write( "-130/3+26=-40/3-4
\n" ); document.write( "-130/3+78/3=-40/3-12/3
\n" ); document.write( "-52/3=-52/3
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