document.write( "Question 56437: I think I get scared of fractions and algebra. I am not sure I ask previously in the correct way. Can you help with this? Thanks!\r
\n" );
document.write( "\n" );
document.write( "solve for x:\r
\n" );
document.write( "\n" );
document.write( " 13 4
\n" );
document.write( "_______ = _______\r
\n" );
document.write( "\n" );
document.write( " x-1 x+2\r
\n" );
document.write( "\n" );
document.write( "or 13 over x-1 equal(=) to 4 over x +2. Maybe that is clear enough. \r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "any assitance would be appreciated.''.
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #38279 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 13/(X-1)=4/(X+2) \n" ); document.write( "CROSS MULTIPLYING WE GET \n" ); document.write( "4(X-1)=13(X+2) \n" ); document.write( "4X-4=13X+26 \n" ); document.write( "4X-13X=26+4 \n" ); document.write( "-9X=30 \n" ); document.write( "X=30/-9 \n" ); document.write( "X=-10/3 \n" ); document.write( "PROOF \n" ); document.write( "13[(-10/3)-1]=4/[(-10/3)+2] \n" ); document.write( "13[(-10/3)+2]=4[(-10/3)-1] \n" ); document.write( "-130/3+26=-40/3-4 \n" ); document.write( "-130/3+78/3=-40/3-12/3 \n" ); document.write( "-52/3=-52/3 \n" ); document.write( " |