document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=607531>Question 607531</A>: <I><SPAN STYLE=\"word-break: break-all;\"> On an assignment, Bob incorrectly solves the left side of the problem:\r<BR>\n" );
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document.write( "12x^3 - 6x / 3x = 4x^2 - 6x\r<BR>\n" );
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document.write( "What mistake do you think he is making?  Please write a short explanation on how the mistake was made. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #382767 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=382767\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Evidently, Bob failed to divide both terms by the divisor.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2812x%5E3-6x%29%2F%283x%29+=+%2812x%5E3%2F3x%29-%286x%2F3x%29 ALIGN=MIDDLE  ALT=\"%2812x%5E3-6x%29%2F%283x%29+=+%2812x%5E3%2F3x%29-%286x%2F3x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >= <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4x%5E2-2 ALIGN=MIDDLE  ALT=\"4x%5E2-2\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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