document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=607528>Question 607528</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Susan has 600 feet of fencing to use in making a yard for her new puppy. The yard she has planned has a length that is 75 feet less than twice the width. What are the dimensions of the yard? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #382759 by </B><A HREF=/tutors/aboutme.mpl?userid=alicealc><B>alicealc(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=alicealc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=382759\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Length = L<BR>\n" );
document.write( "Width = W\r<BR>\n" );
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document.write( "length is 75 feet less than twice the width:<BR>\n" );
document.write( "L = 2W - 75<BR>\n" );
document.write( "perimeter = 600 feet<BR>\n" );
document.write( "perimeter = 2 * (length + width)<BR>\n" );
document.write( "600 = 2 * (2W - 75 + W)<BR>\n" );
document.write( "600/2 = 2W - 75 + W<BR>\n" );
document.write( "300 = 3W - 75<BR>\n" );
document.write( "300 + 75 = 3W<BR>\n" );
document.write( "375 = 3W<BR>\n" );
document.write( "W = 375/3 = 125<BR>\n" );
document.write( "L = 2W - 75 = 2 * 125 - 75 = 250 - 75 = 175\r<BR>\n" );
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document.write( "so the dimension of the yard is:<BR>\n" );
document.write( "length = 175 feet<BR>\n" );
document.write( "width = 125 width<BR>\n" );
document.write( " </SPAN>\n" );
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