document.write( "Question 607492: I believe you solve this word problem with Pythagorean Theorem..\r
\n" ); document.write( "\n" ); document.write( "A rectangle has a diagonal that measures 10 centimeters and a length that is 2 centimeters longer than the width. What is the width of the rectangle in centimeter? \r
\n" ); document.write( "\n" ); document.write( "I'd really appreciate some help!(: \n" ); document.write( "
Algebra.Com's Answer #382745 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
A rectangle has a diagonal that measures 10 centimeters and a length that is 2 centimeters longer than the width. What is the width of the rectangle in centimeter?
\n" ); document.write( ".
\n" ); document.write( "Let w = width
\n" ); document.write( "then
\n" ); document.write( "w+2 = length
\n" ); document.write( ".
\n" ); document.write( "applying Pythagorean theorem:
\n" ); document.write( "w^2 + (w+2)^2 = 10^2
\n" ); document.write( "w^2 + (w+2)(w+2) = 100
\n" ); document.write( "w^2 + w^2+4w+4 = 100
\n" ); document.write( "2w^2+4w+4 = 100
\n" ); document.write( "2w^2+4w-96 = 0
\n" ); document.write( "2w^2+16w-12w-96 = 0
\n" ); document.write( "(2w^2+16w)-(12w+96) = 0
\n" ); document.write( "2w(w+8)-12(w+8) = 0
\n" ); document.write( "(w+8)(2w-12) = 0
\n" ); document.write( "w = {-8, 12/2}
\n" ); document.write( "w = {-8, 6}
\n" ); document.write( "Throw out the negative solution (extraneous) leaving:
\n" ); document.write( "w = 6 cm
\n" ); document.write( " \n" ); document.write( "
\n" );