document.write( "Question 607388: How much of a 40% antifreeze solution must a mechanic mix with an 80% antifreeze solution if 20 gallons of a 50% antifreeze solution are needed?\r
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document.write( "Here's what I tried:\r
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document.write( "Let x= amount of 40%, y= amount of 80%\r
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document.write( "0.40x + 0.80y = 0.5(20)
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document.write( "x + y = 20\r
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document.write( "Multiplied by 10 to get rid of decimals in first equation:\r
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document.write( "4x + 8y = 10
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document.write( "x + y = 20\r
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document.write( "Put into matrices and got:\r
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document.write( "(37.5, -17.5)\r
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document.write( "The answer is supposed to equal to 15 gal of 40%, 5 gal of 80% according to the lab worksheet I'm working on. I don't know what I am doing wrong. \n" );
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Algebra.Com's Answer #382702 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " |