document.write( "Question 607388: How much of a 40% antifreeze solution must a mechanic mix with an 80% antifreeze solution if 20 gallons of a 50% antifreeze solution are needed?\r
\n" ); document.write( "\n" ); document.write( "Here's what I tried:\r
\n" ); document.write( "\n" ); document.write( "Let x= amount of 40%, y= amount of 80%\r
\n" ); document.write( "\n" ); document.write( "0.40x + 0.80y = 0.5(20)
\n" ); document.write( "x + y = 20\r
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\n" ); document.write( "\n" ); document.write( "Multiplied by 10 to get rid of decimals in first equation:\r
\n" ); document.write( "\n" ); document.write( "4x + 8y = 10
\n" ); document.write( "x + y = 20\r
\n" ); document.write( "\n" ); document.write( "Put into matrices and got:\r
\n" ); document.write( "\n" ); document.write( "(37.5, -17.5)\r
\n" ); document.write( "\n" ); document.write( "The answer is supposed to equal to 15 gal of 40%, 5 gal of 80% according to the lab worksheet I'm working on. I don't know what I am doing wrong.
\n" ); document.write( "

Algebra.Com's Answer #382702 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi
\n" ); document.write( "Let x= amount of 40%, y= amount of 80%
\n" ); document.write( "0.40x + 0.80y = 0.5(20)
\n" ); document.write( " x + y = 20 OR x = 20-y
\n" ); document.write( "good Work! substituting (20-y) for x
\n" ); document.write( "0.40(20-y) + 0.80y = 0.5(20)
\n" ); document.write( " .40y = .5(20)-.40(20)
\n" ); document.write( " y = .10(20)/.40
\n" ); document.write( " y = 5 gal of the 80% solution and 15gal of the 40% solution (5 + 15 = 20) \n" ); document.write( "
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