document.write( "Question 607408: Where do i start to set this up?
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document.write( "Suppose that 79,000 is invested at 5 and 1/2% interest, compounded quarterly .
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document.write( "(a) find the function for the amount to which the investment grows after t years.
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document.write( "(b) find the amount of money in the account at t=0,3,7,10 years.
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document.write( "(c)when will the amount of money reach $300,000? \n" );
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Algebra.Com's Answer #382672 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Suppose that 79,000 is invested at 5 and 1/2% interest, compounded quarterly . \n" ); document.write( "(a) find the function for the amount to which the investment grows after t years. \n" ); document.write( "--- \n" ); document.write( "A(t) = P(1+(r/n))^(nt) \n" ); document.write( "A(t) = 79000(1+(0.055/4))^(4t) \n" ); document.write( "------------------------------------- \n" ); document.write( "(b) find the amount of money in the account at t=0,3,7,10 years. \n" ); document.write( "Substitute each of those numbers for \"t\" to find A(t) \n" ); document.write( "-------------------------------------- \n" ); document.write( "(c)when will the amount of money reach $300,000? \n" ); document.write( "Solve: 300,000 = 79000(1+(0.055/4))^(4t) \n" ); document.write( "3.7975 = (1.01375)^(4t) \n" ); document.write( "--- \n" ); document.write( "Take the log of both sides to get: \n" ); document.write( "4t*log(1.01375) = log(3.7975) \n" ); document.write( "4t = 97.71 \n" ); document.write( "time = 24.4 years \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |