document.write( "Question 607381: body temps: mean of 96.20 standard deviation of .82
\n" ); document.write( "If you have a body temp of 97.00 degrees, what is your percentile score?
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Algebra.Com's Answer #382659 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "mean of 96.20 standard deviation of .82
\n" ); document.write( "P(X=97) = P(z=(97-96.2)/.82) = P(z= .9756) = .8354 or 83.54%
\n" ); document.write( " Excel function: NORMSDIST(0.9756)= .8354 \n" ); document.write( "
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