document.write( "Question 56405: Please help me solve this equation: 5(2y-1)=3(y-4)
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Algebra.Com's Answer #38265 by Lacey020991(49)\"\" \"About 
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--First: distribute everything.
\n" ); document.write( "--Second: subtract 3y from each side. The 3y's on the left will cancel out.
\n" ); document.write( "--Third: add 5 to each side. The 5's on the left side will cancel out.
\n" ); document.write( "--Fourth: divide each side by 7.
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\n" ); document.write( "5(2y-1) = 3(y-4)
\n" ); document.write( "10y - 5 = 3y - 12
\n" ); document.write( "7y - 5 = -12
\n" ); document.write( "7y = -7
\n" ); document.write( "y = -1
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\n" ); document.write( "ALWAYS check your work:
\n" ); document.write( "5(2y-1) = 3(y-4)
\n" ); document.write( "5(2*-1-1) = 3(-1-4)
\n" ); document.write( "5(-2-1) = 3(-5)
\n" ); document.write( "5(-3) = -15
\n" ); document.write( "-15 = -15 check
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\n" ); document.write( "Hope this helped!
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