document.write( "Question 607288: Graph the function f(x)= -x, X<3,
\n" ); document.write( " 3x-4, x>= 3
\n" ); document.write( "a) fund the domain
\n" ); document.write( "b) locate any intercepts
\n" ); document.write( "c) graph the function
\n" ); document.write( "d) find the range
\n" ); document.write( "e) is f continuous on its domain?
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Algebra.Com's Answer #382626 by KMST(5328)\"\" \"About 
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a) The function is defined in two different ways for x<3 and for \"x%3E=3\", but it is defined for all x, so the domain is all the real numbers.
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\n" ); document.write( "b) For x<3, f(x)=-x is a straight line going through the origin, since f(0)=0, so you could say that the x-intercept and the y-intercept are (0,0).
\n" ); document.write( "In the other part of the function, for \"x%3E=3\" ,
\n" ); document.write( "\"3x%3E=9\" and \"f%28x%29=3x-4%3E=9-5=4%3E0\" , so there are no intercepts (no x=0 and no y=0) in that part of the function.
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\n" ); document.write( "c)
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\n" ); document.write( "d) f(x)>-3 on both parts of the function, but there is no upper limit. Maybe you would describe the range as (-3,infinity), or maybe you are expected to use a different notation.
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\n" ); document.write( "e) No. The function is obviously discontinuous at x=3. While it is continuous at all other points of its domain, it is not continuous at all points of the domain.
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