document.write( "Question 607218: The length of a rectangle is 4 inches longer than twice its width. The area of the rectangle is 96 square inches. What is the length and the width of the rectangle?
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #382618 by asuar010(338)\"\" \"About 
You can put this solution on YOUR website!
l=2w+4 and the area is 96 so if we set up te equation as l*w=96 and we substitute we obtain 2w^2+4w-96=0
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"aw%5E2%2Bbw%2Bc=0\" (in our case \"2w%5E2%2B4w%2B-96+=+0\") has the following solutons:
\n" ); document.write( "
\n" ); document.write( " \"w%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
\n" ); document.write( "
\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
\n" ); document.write( "
\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%284%29%5E2-4%2A2%2A-96=784\".
\n" ); document.write( "
\n" ); document.write( " Discriminant d=784 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-4%2B-sqrt%28+784+%29%29%2F2%5Ca\".
\n" ); document.write( "
\n" ); document.write( " \"w%5B1%5D+=+%28-%284%29%2Bsqrt%28+784+%29%29%2F2%5C2+=+6\"
\n" ); document.write( " \"w%5B2%5D+=+%28-%284%29-sqrt%28+784+%29%29%2F2%5C2+=+-8\"
\n" ); document.write( "
\n" ); document.write( " Quadratic expression \"2w%5E2%2B4w%2B-96\" can be factored:
\n" ); document.write( " \"2w%5E2%2B4w%2B-96+=+2%28w-6%29%2A%28w--8%29\"
\n" ); document.write( " Again, the answer is: 6, -8.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+2%2Ax%5E2%2B4%2Ax%2B-96+%29\"

\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "and we take the positive answer as the solution for w so l=2(6)+4=12+4=16
\n" ); document.write( "
\n" );