document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=607342>Question 607342</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangular garden has a perimeter of 28 yards, the width of the garden is 6 yards less than its length. what is the area of the garden, in square yards? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #382612 by </B><A HREF=/tutors/aboutme.mpl?userid=asuar010><B>asuar010(338)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=asuar010><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=asuar010><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=382612\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 2(l+w)=28 which leads to l+w=14 and by following the problem we get that w=l-6 and by subtituting we get l+(l-6)=14 which leads to 2l=20 and l=10 which leads to w=4 so teh area=l*w=10*4=40 </SPAN>\n" );
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