document.write( "Question 607321: An oil tank is constructed so that the middle part is a cylinder with length 25' and radius 5' and two ends that are each hemispheres. By what percent is the surface area of the tank increased if the length of the cylindrical part of the tank is doubled? Justify your answer.
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Algebra.Com's Answer #382595 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "An oil tank is constructed so that the middle part is a cylinder with length
\n" ); document.write( " 25' and radius 5' and two ends that are each hemispheres.
\n" ); document.write( " Surface Area = 2Ends + around the Cyliner = \"2pi%2Ar%5E2+%2B+2pi%2Arh+=2pi%2Ar%28r%2Bh%29+\"
\n" ); document.write( " Surface Area[1] = 2pi5·30
\n" ); document.write( " Surface Area[2] = 2pi5·55
\n" ); document.write( " 55/30 = 1.83 or 183% \n" ); document.write( "
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