document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=607314>Question 607314</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x^2-2x-12=0  solve using method of completing a square  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #382581 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=382581\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x^2-2x-12=0 solve using method of completing a square <BR>\n" );
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document.write( "Divide thru by 2 to get:<BR>\n" );
document.write( "x^2 - x - 6 = 0<BR>\n" );
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document.write( "Rearrange:<BR>\n" );
document.write( "x^2-x+(1/2)^2 = 6 + (1/2)^2<BR>\n" );
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document.write( "Factor:<BR>\n" );
document.write( "(x-(1/2))^2 = 25/4<BR>\n" );
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document.write( "x-(1/2) = 5/4 or x-(1/2) = -5/4<BR>\n" );
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document.write( "x = (2/4)+(5/4) or x = (2/4)-(5/4)<BR>\n" );
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document.write( "x = 7/4 or x = -3/4<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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