document.write( "Question 607312: In printing an article of 48,000 words, a printer decides to use two sizes of type. Using the larger type, a printed page contains 1,800 words. Using smaller type, a page contains 2,400 words. The article is allotted 21 full pages in a magazine. How many pages must be in smaller type?\r
\n" ); document.write( "\n" ); document.write( "The answer is 17, but how do you get this answer? I don't know what formula to use to solve this \n" ); document.write( "
Algebra.Com's Answer #382574 by Nihal@SriLanka(22)\"\" \"About 
You can put this solution on YOUR website!
Your notion that there is a formula for the solution of such problems is wrong.\r
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\n" ); document.write( "\n" ); document.write( "What we do is we express the given information as a simple algebraic equation with one unknown figure ( In this case the no of pages of smaller type. Note that once you know the pages of smaller type then the pages with large type is 21 less that no )\r
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\n" ); document.write( "\n" ); document.write( "We denote no of small type pages by x representing a no and the equation turns out to be \r
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\n" ); document.write( "\n" ); document.write( " x * 2400 + (21-x) * 1800 = 48000 which we obtain by simply adding the words in all 21 pages assuming small type page no to be x.\r
\n" ); document.write( "\n" ); document.write( "progressively simplifying above equation we have
\n" ); document.write( "2400x + 21 * 1800 - 1800x = 48000
\n" ); document.write( "i.e. 600x = 48000 - 21 * 1800 = 48000 - 37800 = 10200
\n" ); document.write( "i.e. x = 17\r
\n" ); document.write( "\n" ); document.write( "If you need any further clarification you may email sumanapala@gmail.com \n" ); document.write( "
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