document.write( "Question 607220: \n" ); document.write( "
Algebra.Com's Answer #382563 by sophxmai(62)\"\" \"About 
You can put this solution on YOUR website!
The length of a rectangle is 4 inches longer than twice its width. The area of the rectangle is 96 square inches. What is the length and width of the rectangle?\r
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\n" ); document.write( "\n" ); document.write( "Let x=length and y=width
\n" ); document.write( "\"y-4=2x\"
\n" ); document.write( "\"xy=96\"\r
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\n" ); document.write( "\n" ); document.write( "Solve the first equation for y and substitute it into the 2nd equation
\n" ); document.write( "\"y-4=2x\"
\n" ); document.write( "\"y=2x%2B4\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"xy=96\"
\n" ); document.write( "\"x%282x%2B4%29=96\"
\n" ); document.write( "\"2x%5E2%2B4x=96\"
\n" ); document.write( "\"2x%5E2%2B4x-96=0\"
\n" ); document.write( "\"2%28x%5E2%2B2x-48%29\"
\n" ); document.write( "\"2%28x%2B8%29%28x-6%29=0\"
\n" ); document.write( "\"x=-8%2C6\"
\n" ); document.write( "Reject x=-8 because the length cannot be a negative number
\n" ); document.write( "So x=6\r
\n" ); document.write( "\n" ); document.write( "Substitute x to find y
\n" ); document.write( "\"y=2x%2B4\"
\n" ); document.write( "\"y=2%286%29%2B4\"
\n" ); document.write( "\"y=12%2B4\"
\n" ); document.write( "\"y=16\"
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