document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=607291>Question 607291</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There’re three brand of fertilizers A, B, and C. Following is a table of the amount of nitrogen, phosphorus, <BR>\n" );
document.write( "and potassium in a box of each brand (in lb). \r<BR>\n" );
document.write( "\n" );
document.write( "Brand	A	B	C<BR>\n" );
document.write( "N	1	2	2<BR>\n" );
document.write( "P	2	1	2<BR>\n" );
document.write( "K	2	2	1\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "How many boxes of each brand are needed in order to make a mixture that contains 6 lb of nitrogen, 6 lb of phosphorus and 7 lb of potassium? <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #382558 by </B><A HREF=/tutors/aboutme.mpl?userid=LisaJ><B>LisaJ(11)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LisaJ><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=382558\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Set your variables:\r<BR>\n" );
document.write( "\n" );
document.write( "a = boxes of A<BR>\n" );
document.write( "b = boxes of B<BR>\n" );
document.write( "c = boxes of C\r<BR>\n" );
document.write( "\n" );
document.write( "You will get three equations:\r<BR>\n" );
document.write( "\n" );
document.write( "1: For N: a + 2b + 2c = 6<BR>\n" );
document.write( "2: For P: 2a + b + 2c = 6<BR>\n" );
document.write( "3: For K: 2a + 2b + c = 7\r<BR>\n" );
document.write( "\n" );
document.write( "Solve using determinants, if you have studied them. Otherwise solve by elimination of variables:<BR>\n" );
document.write( "Subtract the second equation from the first:<BR>\n" );
document.write( "-a + b = 0<BR>\n" );
document.write( "So a=b.<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Substitute b = a into Eq. 1: 3a + 2c = 6<BR>\n" );
document.write( "Substitute b = a into Eq. 3: 4a +  c = 7\r<BR>\n" );
document.write( "\n" );
document.write( "Solve these together for a = 8/3; c = 3/5.\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );