document.write( "Question 607267: If I have a 55.80% as a grade right now, how many more tests will be needed to be taken and what scores would they need to be to get a 70%? \n" ); document.write( "
Algebra.Com's Answer #382545 by LisaJ(11)![]() ![]() ![]() You can put this solution on YOUR website! It depends on how many tests you have already taken. You need to take the average of all your test scores.\r \n" ); document.write( "\n" ); document.write( "For example, if you have taken one test so far, you can take one more test and get 100%.\r \n" ); document.write( "\n" ); document.write( "(100 + 55.8)2 = 77.9 %\r \n" ); document.write( "\n" ); document.write( "If you get 90% on the second test:\r \n" ); document.write( "\n" ); document.write( "(90 + 55.8)/2 = 72.9 %\r \n" ); document.write( "\n" ); document.write( "If you have taken 4 tests so far, you can take 4 more tests, and get 90% on each. \n" ); document.write( "(4*55.8 + 4*90)/8 = 72.9%\r \n" ); document.write( "\n" ); document.write( "Or take 3 more tests, and get 100% on them: \n" ); document.write( "(4*55.8) + 3*100) /7 = 75%\r \n" ); document.write( "\n" ); document.write( "Or take 5 more tests, and get 82% on them:\r \n" ); document.write( "\n" ); document.write( "(4*55.8) + 5*82) /9 = 70%\r \n" ); document.write( "\n" ); document.write( "Find out how many more test there will be, and then you can figure out how high you have to score on them. \n" ); document.write( " \n" ); document.write( " |