document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=607211>Question 607211</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two cyclists, 72 miles apart, start riding toward each other at the same time, one cyclist 2 times as fast as the other, if they meet 3 hours later, what is the speed(in mi/h) of the faster cyclist </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #382511 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=382511\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> two cyclists, 72 miles apart, start riding toward each other at the same time, one cyclist 2 times as fast as the other, if they meet 3 hours later, what is the speed(in mi/h) of the faster cyclist<BR>\n" );
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document.write( "Let x = speed of faster cyclist<BR>\n" );
document.write( "then<BR>\n" );
document.write( "x/2 = speed of slower cyclist<BR>\n" );
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document.write( "applying the distance formula: d=rt<BR>\n" );
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document.write( "3x + 3x/2 = 72<BR>\n" );
document.write( "multiplying both sides by 2:<BR>\n" );
document.write( "6x + 3x = 144<BR>\n" );
document.write( "9x = 144<BR>\n" );
document.write( "x = 144/9<BR>\n" );
document.write( "x = 16 mph<BR>\n" );
document.write( " </SPAN>\n" );
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