document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=607202>Question 607202</A>: <I><SPAN STYLE=\"word-break: break-all;\"> IF you have 2x^2-89-11 but there is no x after 89 and we are for surely suposed to be dealing with quadratic equations 89 still be the B in the ax^2+bx+c=0? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #382504 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=382504\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> No, combine -89 and -11 to get -100. So the expression simplifies to 2x^2-100.\r<BR>\n" );
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document.write( "You can think of it as 2x^2+0x-100 </SPAN>\n" );
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