document.write( "Question 607182: 27y^3-125x^3 \n" ); document.write( "
Algebra.Com's Answer #382485 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"27y%5E3-125x%5E3\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%283y%29%5E3-%285x%29%5E3\" Rewrite \"27y%5E3\" as \"%283y%29%5E3\". Rewrite \"125x%5E3\" as \"%285x%29%5E3\".\r
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\n" ); document.write( "\n" ); document.write( "\"%283y-5x%29%28%283y%29%5E2%2B%283y%29%285x%29%2B%285x%29%5E2%29\" Now factor by using the difference of cubes formula. Remember the difference of cubes formula is \"A%5E3-B%5E3=%28A-B%29%28A%5E2%2BAB%2BB%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%283y-5x%29%289y%5E2%2B15xy%2B25x%5E2%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So \"27y%5E3-125x%5E3\" factors to \"%283y-5x%29%289y%5E2%2B15xy%2B25x%5E2%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"27y%5E3-125x%5E3=%283y-5x%29%289y%5E2%2B15xy%2B25x%5E2%29\"\r
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