document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=607174>Question 607174</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please can you help me with this problem. I really do appreciate your help...\r<BR>\n" );
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document.write( "The width of a rectangle is 6 kilometers less than twice its length if its area is 80 square kilometers find the dimensions of the rectangle?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #382482 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=382482\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 6 kilometers less than twice its length if its area is 80 square kilometers find the dimensions of the rectangle?<BR>\n" );
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document.write( "let x=length<BR>\n" );
document.write( "2x-6=width<BR>\n" );
document.write( "Area=length*width<BR>\n" );
document.write( "80=x(2x-6)=2x^2-6x<BR>\n" );
document.write( "2x^2-6x-80=0<BR>\n" );
document.write( "x^2-3x-40=0<BR>\n" );
document.write( "(x-8)(x+5)=0<BR>\n" );
document.write( "x=-5 (Reject)<BR>\n" );
document.write( "or<BR>\n" );
document.write( "x=8<BR>\n" );
document.write( "2x-6=10<BR>\n" );
document.write( "ans:<BR>\n" );
document.write( "length=8 km<BR>\n" );
document.write( "width=10 km<BR>\n" );
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