document.write( "Question 607157: a. Mike and Scott live 110 miles from each other. They frequently meet for lunch at a restaurant that is between Mike’s house and Scott’s house. Leaving at the same time from their respective houses, Mike takes 1 hour and 30 minutes and Scott takes 1 hour and 15 minutes to get to the restaurant. If they each drive at the same speed,
\n" ); document.write( "i. Determine their speed
\n" ); document.write( "ii. How far from Scott’s house is the restaurant?
\n" ); document.write( "Thank you!
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Algebra.Com's Answer #382461 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+d+\" = distance from Scott's house to restaurant
\n" ); document.write( "\"+110+-+d+\" = distance from Mike's house to restaurant
\n" ); document.write( "\"+s+\" = speed for both Mike and Scott
\n" ); document.write( "----------------
\n" ); document.write( "Scott's equation:
\n" ); document.write( "(1) \"+d+=+s%2A1.25+\"
\n" ); document.write( "Mike's equation:
\n" ); document.write( "(2) \"+110+-+d+=+s%2A1.5+\"
\n" ); document.write( "---------------------------
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) \"+110+-+1.25s+=+1.5s+\"
\n" ); document.write( "(2) \"+2.75s+=+110+\"
\n" ); document.write( "(2) \"+s+=+40+\" mi/hr
\n" ); document.write( "------------
\n" ); document.write( "Both speeds are 40 mi/hr
\n" ); document.write( "(1) \"+d+=+s%2A1.25+\"
\n" ); document.write( "(1) \"+d+=+40%2A1.25+\"
\n" ); document.write( "(1) \"+d+=+50+\"
\n" ); document.write( "Scott's house is 50 mi from restaurant
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+110+-+d+=+s%2A1.5+\"
\n" ); document.write( "(2) \"+110+-+d+=+40%2A1.5+\"
\n" ); document.write( "(2) \"+110+-+d+=+60+\"
\n" ); document.write( "(2) \"+d+=+110+-+60+\"
\n" ); document.write( "(2) \"+d+=+50+\"
\n" ); document.write( "OK
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