document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=607109>Question 607109</A>: <I><SPAN STYLE=\"word-break: break-all;\"> have a container openning of 90\" tall and 92\" wide, how do i get the the distance from the bottom righthand corner to the top of the lefthand corner of the openning ? it has been a while since i used that type of math.\r<BR>\n" );
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document.write( "thanks in advance for your help<BR>\n" );
document.write( "Dan  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #382413 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=382413\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> have a container openning of 90\" tall and 92\" wide, how do i get the the distance from the bottom righthand corner to the top of the lefthand corner of the openning ? it has been a while since i used that type of math.<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d+=+sqrt%2890%5E2+%2B+92%5E2%29+=+sqrt%2816564%29 ALIGN=MIDDLE  ALT=\"d+=+sqrt%2890%5E2+%2B+92%5E2%29+=+sqrt%2816564%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "d =~ 128.7 inches<BR>\n" );
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